Asked by susan
A 0.55-{kg} croquet ball is initially at rest on the grass. When the ball is struck by a mallet, the average force exerted on it is 220 N. If the ball's speed after being struck is 3.2 m/s, how long was the mallet in contact with the ball?
Answers
Answered by
pms
force=change in momentum/time
time=(mass * velocity)-(0)/220 N
t=(0.55 kg*3.2)/220N
=0.008 s
time=(mass * velocity)-(0)/220 N
t=(0.55 kg*3.2)/220N
=0.008 s
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