Asked by Cecille
Use algebra to evaluate the limit lim h->0((2−h)^2−8)/h
Answers
Answered by
Reiny
just expand the expression ...
((2−h)^2−8)/h
= (4 - 4h + h^2 - 8)/h
I sense something is wrong here, are you sure it wasn't
lim ((2-h)^3 - 8)/h ????
then it would make sense.
((2−h)^2−8)/h
= (4 - 4h + h^2 - 8)/h
I sense something is wrong here, are you sure it wasn't
lim ((2-h)^3 - 8)/h ????
then it would make sense.
Answered by
Cecille
I'm sorry, yeah it's ((2-h)^3 - 8)/h
Answered by
Reiny
ok, expand that ...
((2−h)^3−8)/h
=( 8 - 12h + 6h^2 - h^3 - 8)/h
= (-12 + 6h - h^2)
so lim (-12 + 6h - h^2) as h ---> 0
= -12
((2−h)^3−8)/h
=( 8 - 12h + 6h^2 - h^3 - 8)/h
= (-12 + 6h - h^2)
so lim (-12 + 6h - h^2) as h ---> 0
= -12
Answered by
Cecille
Oh ok... thanks a lot, I was typing 12 all this time....
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.