Use algebra to evaluate the limit lim h->0((2−h)^2−8)/h

Answer 1

just expand the expression ...
((2−h)^2−8)/h
= (4 - 4h + h^2 - 8)/h

I sense something is wrong here, are you sure it wasn't
lim ((2-h)^3 - 8)/h ????
then it would make sense.

Answer 2

I'm sorry, yeah it's ((2-h)^3 - 8)/h

Answer 3

ok, expand that ...
((2−h)^3−8)/h
=( 8 - 12h + 6h^2 - h^3 - 8)/h
= (-12 + 6h - h^2)

so lim (-12 + 6h - h^2) as h ---> 0
= -12

Answer 4

Oh ok... thanks a lot, I was typing 12 all this time....