Question
The area of a rectangular playground is 2,700 ft2. The length is 3
times the width.What are the dimensions of the playground?
times the width.What are the dimensions of the playground?
Answers
Bosnian
L=Lenght
W=Width
A=L*W
L=3W
2700=3W*W
2700=3W^2 Diwide with 3
2700/3=W^2
W^2=900
W=sqroot(900)=30ft
L=3W=3*30=90ft
L=90ft W=30ft
A=L*W=90*30=2700ft^2
W=Width
A=L*W
L=3W
2700=3W*W
2700=3W^2 Diwide with 3
2700/3=W^2
W^2=900
W=sqroot(900)=30ft
L=3W=3*30=90ft
L=90ft W=30ft
A=L*W=90*30=2700ft^2