Question

arrange the following compounds in the order of increasing polarity HF, H2SE, N2, H2s

I believe that the answer is
H2Se < H2S < N2 < HF
Is that correct?
Wouldn't you think N2 would be the least polar of all? I would move N2 to the least polar. The order of the others appears ok.
To this
N2 < H2Se < H2S < HF

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