Asked by Anonymous
In a distant planet, a freely falling object gains speed at a steady rate of 25 m/s during each 1.2 seconds of fall. The gravity acceleration there is:
122 m/s2
0.05 m/s2
30 m/s2
22 m/s2
5 m/s2
20.8 m/s2
122 m/s2
0.05 m/s2
30 m/s2
22 m/s2
5 m/s2
20.8 m/s2
Answers
Answered by
Henry
a = 25m/s / 1.2s = 20.8m/s^2.
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