Asked by CS

Heights of males are norm. dist. w/ u=180cm and o^2=16cm^2 while female heights have u=170cm and o^2=25cm^2.

a)random male and female selected. What is the probability that the male is >5 cm taller? What is the distribution avg of the 2 heights?
b)what is the distribution of the avg of the 2 heights?

Answering as much as possible would be amazing! :)
Answered by PsyDAG
Proofread your questions before you post them.

Even as the variance, height is a linear dimension and is not squared.
Answered by CS
I know it's just a linear dimension, I'm just assuming it's my prof's mistake (as he squared the sd to get variance). I simply copied directly from the paper.
Answered by Noko#1
The heights of women are normally distributed with a mean of 63.6 inches and a standard deviation of 2.5 inches. The U.S Army require's women's heights of 58 inches and 80 inches. Find the percentage.
Answered by Anonymous
Suppose that people's heights (in centimeters) are normally distributed, with a mean of 175 and a standard deviation of 6. We find the heights of 40 people.
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