Asked by Anonymous

A 751 N diver drops from a board 9.10 m
above the water’s surface.
The acceleration of gravity is 9.81 m/s2 .
a) Find the diver’s speed 3.00 m above the
water’s surface.
Answer in units of m/s.

Answers

Answered by bobpursley
KE final= PE initial
1/2 mv^2=mgh
solve for v.
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