Asked by Elton luthuli
A motorbike accelerates uniformly at 0.6m.s for 10s. If it covers a distance of 500m. During this time, what was its initial velocity?
Answers
Answered by
drwls
The acceleration should have units of m/s^2 so I will assume it is
0.6 m/s^2
The average velocity during the period is 500/10 = 50 m/s = (V2 + V1)/2, so
V2 + V1 = 100
You also know that
V2 - V1 = a * 10s = 6 m/s
Therefore
2 V2 = 106
V2 = 53
V1 = 47 is the initial velocity
0.6 m/s^2
The average velocity during the period is 500/10 = 50 m/s = (V2 + V1)/2, so
V2 + V1 = 100
You also know that
V2 - V1 = a * 10s = 6 m/s
Therefore
2 V2 = 106
V2 = 53
V1 = 47 is the initial velocity
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