Asked by Linda
If a triangle has angle measures 15, 120 and 45, and the length of the side between the 15 and 120 angles is 8, what is the area of the triangle?
Answers
Answered by
drwls
Let A = 15, B = 120 and C = 45 degrees
The side with length 8 is opposite the 45 degree angle. (side c)
sinC/c = sinB/b = sin A/a = 0.08839
b = 9.798
a = 2.928
c = 8.000
Area = (1/2) bc sin A
= 10.14 square length units
The side with length 8 is opposite the 45 degree angle. (side c)
sinC/c = sinB/b = sin A/a = 0.08839
b = 9.798
a = 2.928
c = 8.000
Area = (1/2) bc sin A
= 10.14 square length units
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