Asked by olivia
Locomotive exert on a 13160-kg boxcar to make it accelerate forward at 0.40 m/s2. How long will it take the boxcar to reach its cruising speed of 105 km/h (65.2 mph or 29.2 m/s)?
Answers
Answered by
olga
29.2m/s= t*.40m/s^2+0
t=29.2m/s/.40m/s^2
t=73s
t=29.2m/s/.40m/s^2
t=73s
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