Asked by Andy
Explain the differences between solving these two equations:
Brake down the steps.
log3(x - 1) = 4 and log3(x - 1) = log34 )
Brake down the steps.
log3(x - 1) = 4 and log3(x - 1) = log34 )
Answers
Answered by
Henry
1. log3(x - 1) = 4.
x - 1 = 3^4,
x = 3^4 + 1 = 81 + 1 = 82.
2. log3(x - 1) = log34.
log3(x - 1) = 1.5315,
x - 1 = 3^1.5315,
x = 3^1.5315 + 1 = 5.379 + 1 = 6.379.
Each problem required the use and understanding 0f logs. So they were basically the same.
x - 1 = 3^4,
x = 3^4 + 1 = 81 + 1 = 82.
2. log3(x - 1) = log34.
log3(x - 1) = 1.5315,
x - 1 = 3^1.5315,
x = 3^1.5315 + 1 = 5.379 + 1 = 6.379.
Each problem required the use and understanding 0f logs. So they were basically the same.
Answered by
Henry
2. log3(x - 1) = log3(4).
If two numbers have equal logs, they are equal:
x-1 = 4,
x = 4 + 1 = 5.
If two numbers have equal logs, they are equal:
x-1 = 4,
x = 4 + 1 = 5.
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