Asked by Andy
Explain the differences between solving these two equations:
•log3(x - 1) = 4
AND log3(x - 1) = log34
I think it has to deal with the formulas?
•log3(x - 1) = 4
AND log3(x - 1) = log34
I think it has to deal with the formulas?
Answers
Answered by
Reiny
by definition
log3(x - 1) = 4
is 3^4 = x-1
x= 82
for the second, (I will assume you meant
log<sub>3</sub>(x - 1) = log<sub>3</sub>4 )
anti-log it
x-1 = 4
x = 5
log3(x - 1) = 4
is 3^4 = x-1
x= 82
for the second, (I will assume you meant
log<sub>3</sub>(x - 1) = log<sub>3</sub>4 )
anti-log it
x-1 = 4
x = 5
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