by definition
log3(x - 1) = 4
is 3^4 = x-1
x= 82
for the second, (I will assume you meant
log3(x - 1) = log34 )
anti-log it
x-1 = 4
x = 5
Explain the differences between solving these two equations:
•log3(x - 1) = 4
AND log3(x - 1) = log34
I think it has to deal with the formulas?
1 answer