Asked by Jessica
Gold can be recovered from sea water by reacting the water with zinc, which is refined from zinc oxide. The zinc displaces the gold in the water. What mass of gold can be recovered if 2.00g of ZnO and an excess of sea water are available?
2ZnO + C -> 2Zn + CO2
2Au^+3 + 3Zn -> 3Zn^+2 + 2Au
2ZnO + C -> 2Zn + CO2
2Au^+3 + 3Zn -> 3Zn^+2 + 2Au
Answers
Answered by
bobpursley
6ZnO+ 3C + 4Au+3 >> 6Zn+2 + 4Au + 3CO2
so for each mole of ZnO consumed, one gets 4/6 mole of Gold
massgold=2gZnO*1moleZnO/molmassAuO * 2 moleAu/3moleZnO * molmassAu/1moleAu
so for each mole of ZnO consumed, one gets 4/6 mole of Gold
massgold=2gZnO*1moleZnO/molmassAuO * 2 moleAu/3moleZnO * molmassAu/1moleAu
Answered by
Jessica
Could you break that down a little? I don't completely understand.
Answered by
DrBob222
You're just working another stoichiometry problem.
2 g ZnO = how many moles.
moles = grams/molar mass.
??moles ZnO x (4 moles Au/6 moles ZnO = xx moles Au.
Convert moles Au to grams.
2 g ZnO = how many moles.
moles = grams/molar mass.
??moles ZnO x (4 moles Au/6 moles ZnO = xx moles Au.
Convert moles Au to grams.
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