Question

Set up and evaluate the definite integral for the area of the surface generated by revolving the curve about the y-axis.

y = cube rt. (x) + 2

Thank you so much!!

Answer 1

You need parentheses.

Is your problem,
y = (cubert(x)) + 2
y = (cubert(x + 2))

Answer 2

I hit post, just as I realized what you meant. Sorry.

Since the parentheses are around the (x),
you most likely mean,
y = (cubert(x)) + 2.