Asked by Michaela

Factor these:
8x^3-125
81x^-625
18x^3+63x^2-50x-175
x^4-11x^2+18


I'm so lost!
Answered by bobpursley
differece of cubes
differece of cubes
9x^2(2x+7)-25(2x+7) then gather the common factor, to (2x+7)(9x^2-25), and now the second term is a differece of squares, so It can be factored.
Last
(x^2-9)(x^2-2) both of these terms are difference of squares. (last term (x-sqrt2)(x+sqrt2)
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