group

Question

rh+ 39 35 8 4
rh- 6 5 2 1

People with blood type AB and rh+ are considered to be universal recipients. If three of the 100 subjects are selected find the probability they are all universal recipients.

Answer 1

Just did the exam for this course last week.

So there are 86 people out of 100 who are universal recipients, while the other 14 aren't. (I think that's what your data is telling me.)

We can use the binomial probability formula:

P(X=r)=nCr(p^r)((p-1)^(n-r))

So since we choose 3 people, r=3
and we know that the probability that one person out of those hundred people is 86/100, which can be simplified to 43/50, so we know that p=43/50
There are 100 people, so n=100

So:

P(X=3)=100C3((43/50)^3)((43/50-1)^(100-3))

And solve! :)
If you have any questions about what I did, just ask.

Answer 2

so there is data missing. I am not sure of the answer but I do know the question. in order the blood types are O A B AB so i think only 4 are universal.