Question
If the first term of an arithmetic sequence is 10 and the 13th term is 58, what is the common difference?
Answers
helper
The nth term of an arithmetic progression is defined by
n = a + (n-1)d where,
n = the nth term
a = the first term
d = the common difference
Therefore,
58 = 10 + (13 - 1)d
48 = 12d
d = 4
n = a + (n-1)d where,
n = the nth term
a = the first term
d = the common difference
Therefore,
58 = 10 + (13 - 1)d
48 = 12d
d = 4
Jack
Find the 53rd term of the arithmetic sequence -12,-1,10