Question

A 2.40 m length of wire is held in an east-west direction and moves horizontally to the north with a speed of 14.9 m/s. The vertical component of Earth's magnetic field in this region is 40.0 µT directed downward. Calculate the induced emf between the ends of the wire and determine which end is positive.

Answer 1

E=B*l*v*cos(theta)
=(40)(0.024)(14.9)cos(0)<---east-west
solve, the answer is in micro teslas
west end in positive direction