Asked by Adam
Graph the parabola
x^2+8x-5y+21=0
x^2+8x-5y+21=0
Answers
Answered by
helper
I can't graph this for you.
What do you not understand about graphing?
Pick values for x and solve for y.
After you get a handful of x,y values, plot the points for your graph.
What do you not understand about graphing?
Pick values for x and solve for y.
After you get a handful of x,y values, plot the points for your graph.
Answered by
Reiny
x^2 + 8x ..... + 21 = 5y
x^2 + 8x + 16 - 16 + 21 = 5y
(x+4)^2 + 5 = 5y
y = (1/5)(x+4)^2 + 1
Can you read the vertex from that?
Can you pick some suitable values of x to find a few other points for graphing ?
x^2 + 8x + 16 - 16 + 21 = 5y
(x+4)^2 + 5 = 5y
y = (1/5)(x+4)^2 + 1
Can you read the vertex from that?
Can you pick some suitable values of x to find a few other points for graphing ?
Answered by
Adam
don't I need to put it in y= formula first?
Answered by
Adam
Sorry didn't see Reiny's post
Answered by
Adam
I'm not sure I will look over my notes to see what I come up with.
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