Calculate the mole fraction of the solute in the following aqueous solution:

Question

a) .112M C6H12O6 (d=1.006g/ml).
b) 3.2% ethanol, by volume (d=.993g/ml);
pure CH3CH2OH, d=.789g/ml

Answer 1

0.112M = 0.112 moles/L soln.

0.112 M x molar mass = grams C6H12O6 = ??

1000 mL x 1.006 g/mL = mass soln = ??
mass soln - mass solute = mass solvent

Convert mass solvent to moles.
mole fraction solute = moles solute/total moles.