Asked by emerald
Calculate the mole fraction of the solute in the following aqueous solution:
a) .112M C6H12O6 (d=1.006g/ml).
b) 3.2% ethanol, by volume (d=.993g/ml);
pure CH3CH2OH, d=.789g/ml
a) .112M C6H12O6 (d=1.006g/ml).
b) 3.2% ethanol, by volume (d=.993g/ml);
pure CH3CH2OH, d=.789g/ml
Answers
Answered by
DrBob222
0.112M = 0.112 moles/L soln.
0.112 M x molar mass = grams C6H12O6 = ??
1000 mL x 1.006 g/mL = mass soln = ??
mass soln - mass solute = mass solvent
Convert mass solvent to moles.
mole fraction solute = moles solute/total moles.
0.112 M x molar mass = grams C6H12O6 = ??
1000 mL x 1.006 g/mL = mass soln = ??
mass soln - mass solute = mass solvent
Convert mass solvent to moles.
mole fraction solute = moles solute/total moles.
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