Asked by Confused
(2x(tothe2ndpower)-3x+4)-(3x(tothe2ndpower)-x+2= ????
Answers
Answered by
Reiny
2x^2 - 3x + 4 - (3x^2 - x + 2) = 0
-x^2 - 2x + 2 = 0
x^2 + 2x - 2 = 0
I will complete the square, in this case it is easier than using the formul
x^2 + 2x + 1 = 2+1
(x+1)^2 = 3
x+1 = ± ?3
x = -1 ± ?3
-x^2 - 2x + 2 = 0
x^2 + 2x - 2 = 0
I will complete the square, in this case it is easier than using the formul
x^2 + 2x + 1 = 2+1
(x+1)^2 = 3
x+1 = ± ?3
x = -1 ± ?3
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