Asked by Kinetic Energy
                In a head-on, inelastic collision, a 4000 kg truck going 10 m/s east strikes a 1000 kg 
car going 20 m/s west.
(a) What are the speed and the direction of the wreckage?
(b) How much kinetic energy is lost in the collision?
            
        car going 20 m/s west.
(a) What are the speed and the direction of the wreckage?
(b) How much kinetic energy is lost in the collision?
Answers
                    Answered by
            drwls
            
    a) It is a head-on collision.
Momentum is conserved.
The final momentum (measured positive east) is 4000*10 -1000*20 = 20,000 kg m/s
Set that equal to (M1 + M2)*Vfinal
and solve for Vfinal.
b) Compute the (1/2)M1*V1^2 + (1/2)M2*V2^2 with
(1/2)(M1+M2)Vfinal^2
The latter will be less. The firrence will be the kinetic ene4rgy lost./
    
Momentum is conserved.
The final momentum (measured positive east) is 4000*10 -1000*20 = 20,000 kg m/s
Set that equal to (M1 + M2)*Vfinal
and solve for Vfinal.
b) Compute the (1/2)M1*V1^2 + (1/2)M2*V2^2 with
(1/2)(M1+M2)Vfinal^2
The latter will be less. The firrence will be the kinetic ene4rgy lost./
                    Answered by
            Alison 
            
    50,000
    
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