Asked by Renee

The citizens of Paris were terrified during World War I when they were suddenly bombarded with shells fired from a long-range gun known as Big Bertha. The barrel of the gun was 36.6 m long and it had a muzzle speed of 1.48 km/s. When the gun's angle of elevation was set to 49°, what would be the range? For the purposes of solving this problem, neglect air resistance.

Answered by drwls
Range = 2(V^2/g)sin49cos49
= (V^2/g)sin98 = 2.21*10^5 m = 221 km
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