Asked by Nabil
a 900 N running back moving at 2.0 m/s is stoppped in 0.70 seconds when hit by a lineback. What average foarce did the linebacker exert on the running back?
How much did the running back's momentum change?
How much did the running back's momentum change?
Answers
Answered by
Jack
F = m*a
900N = m*(9.8m/s^2)
m = 91.8367 kg
a = (change in velocity) / (change in time)
a = (Vf - Vi) / (change in time)
a = (2 - 0) / (.7) = 2.85714 m/s^2
F = 91.8367 kg * 2.8571 m/s^2 = 262.391 N
900N = m*(9.8m/s^2)
m = 91.8367 kg
a = (change in velocity) / (change in time)
a = (Vf - Vi) / (change in time)
a = (2 - 0) / (.7) = 2.85714 m/s^2
F = 91.8367 kg * 2.8571 m/s^2 = 262.391 N
Answered by
Jack
change in momentum:
p = m*(change in velocity)
p = 91.8367 kg * (2 m/s) = 183.673 kg*m/s
p = m*(change in velocity)
p = 91.8367 kg * (2 m/s) = 183.673 kg*m/s
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