To melt the ice you have
48*heat fusion = ?
To raise T from zero to 50 C you have
48 x specific heat H2O x (50-0) = ?
Total you need to melt the ice and raise it to 50 C is ? + ?
You get x grams steam x heat condensation = ?
You get x grams H2O from steam x specific heat H2O x (100-50) = ?
The total you get from steam is ?x + ?x
Set them equal to each other and solve for x = grams steam. I did a quickie calculation and came up with about 10 or 11 grams.
48g of ice at its melting point is heated with steam at its condensation point. The final temperature of the system is 50 degree Celsius. How much steam was used to melt the ice?
q=(48g)(1mol/18g)(50-0C)(0.97kcal/mol*C) = 129kcal
Not sure where to go from here (or if that first part is even right)?
2 answers
I understand up to the part about x grams of steam. Is x grams water from steam something I'm supposed to know or no? Also why am I totaling up ?x +?x, but then setting them equal to each other...? Can you explain that last part in more details, please? Thank you so much!!