I really am trying to work these problems out on my own. Please help

Question

If f(x)=3x^2 g(x)= 1/6+x find the following and give the domain

(f+g) (x) (3x^2) + (1/6+x)
x is all real numbers and x is not equal to 6
(f-g) (x) (3x^2) - (1/6+x) 3x^2-x-6
x is all real numbers and x is not equal to -6
(f x g) (x) (f/g) (x) 3x^2/6-x
18x^3-x
x is all real numbers
(f/g)(x) 3x^2/ 1/6+x
x is all real numbers; x is not equal to 6