Question
Dayle is paddling his canoe upstream, against the current, to a fishing spot 10 miles always. If he paddles upstream for 2.5 hours and his return trip takes 1.25 hours, find the speed of the current, and his still water????????
Answers
V = his speed in still water
v = the speed of the current
10/(V-v) = 2.5 and 10/(V+v) = 1.25
SOlve each for V and equate the results yields (10 + 2.5v)/2.5 = (10 - 1.25)/1.25.
Solve for v and then V.
v = the speed of the current
10/(V-v) = 2.5 and 10/(V+v) = 1.25
SOlve each for V and equate the results yields (10 + 2.5v)/2.5 = (10 - 1.25)/1.25.
Solve for v and then V.
Related Questions
I've been working on this one and I just can't figure it out. I appreciate all the help:
Two mil...
When Neil was 2 miles upstream from camp on a canoe trip, he passed a log floating downstream with t...
Petra, who can paddle her canoe at a rate of 12 mph in calm water, is paddling her canoe on a river...
The total time it takes for a canoe to go 3 miles upstream (against current) and back 3 miles downst...