Asked by Candice Watt
Dayle is paddling his canoe upstream, against the current, to a fishing spot 10 miles always. If he paddles upstream for 2.5 hours and his return trip takes 1.25 hours, find the speed of the current, and his still water????????
Answers
Answered by
tchrwill
V = his speed in still water
v = the speed of the current
10/(V-v) = 2.5 and 10/(V+v) = 1.25
SOlve each for V and equate the results yields (10 + 2.5v)/2.5 = (10 - 1.25)/1.25.
Solve for v and then V.
v = the speed of the current
10/(V-v) = 2.5 and 10/(V+v) = 1.25
SOlve each for V and equate the results yields (10 + 2.5v)/2.5 = (10 - 1.25)/1.25.
Solve for v and then V.
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