Question
A fox fleeing from a hunter encounters a 0.625 m tall fence and attempts to jump it. The fox jumps with an initial velocity of 7.75 m/s at an angle of 45.0°, beginning the jump 1.82 m from the fence. By how much does the fox clear the fence? Treat the fox as a particle.
Answers
Henry
Y = ver = 7.75sin45 = 5.48m/s.
(Vf)^2 = (Vi)^2 + 2gd = 0,
(5.48)^2 + 2(-9.8)d = 0,
30.03 - 19.6d = 0,
-19.6d = -30.03,
d(up) = -30.03 / -19.6 = 1.53m.
Margin = 1.53 - 0.625 = 0.91m.
(Vf)^2 = (Vi)^2 + 2gd = 0,
(5.48)^2 + 2(-9.8)d = 0,
30.03 - 19.6d = 0,
-19.6d = -30.03,
d(up) = -30.03 / -19.6 = 1.53m.
Margin = 1.53 - 0.625 = 0.91m.