Question
Two circles of equal radius intersect each other such that each circle passes through the center of the other circle. Find the equation for the perimeter of this figure.
Answers
MathMate
We assume the y-axis to be the common chord, i.e. the centres of the circles are at (-r/2,0) and (r/2,0).
The two circles will therefore respectively be:
(x+r/2)²+y²=r² (x≤0)
and
(x-r/2)²+y²=r² (x≥0)
The two circles will therefore respectively be:
(x+r/2)²+y²=r² (x≤0)
and
(x-r/2)²+y²=r² (x≥0)
tchrwill
The equation for the perimeter of the two intersecting circles of radius R is
P = 2(Pi)R(2)240/360 = 8PiR/3.
P = 2(Pi)R(2)240/360 = 8PiR/3.