Asked by beth
(2 questions)
Factor each expressions
1) 2c + 2d - cd - d^2
2) abd - abe + acd -ace
First rearrange:
2c - cd + 2d - d^2 =
c(2-d)+d(2-d)=
(2-d)(c+d).
The second one is done using the same kind of procedure. Post your work and tell us what you don't understand if you get stuck.
Factor each expressions
1) 2c + 2d - cd - d^2
2) abd - abe + acd -ace
First rearrange:
2c - cd + 2d - d^2 =
c(2-d)+d(2-d)=
(2-d)(c+d).
The second one is done using the same kind of procedure. Post your work and tell us what you don't understand if you get stuck.
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