Asked by Elizabeth
When you freeze water, 80 calories of heat are released into the surroundings for every gram of water that freezes. This is known as the "latent heat of fusion" of water, which is 80 cal/g. Heat of fusion is a characteristic property. Theoretically, if you could "capture" all the heat that is released into a tightly sealed container, by freezing 10 gallons of water: How much heat would you be obtaining?
Answers
Answered by
drwls
One gallon of water weighs 8.35 lb and has a mass of
8.35 lbm*454 g/lbm = 3791 g
Multiply that by the heat of fusion (per gram)
Your answer will be in calories.
8.35 lbm*454 g/lbm = 3791 g
Multiply that by the heat of fusion (per gram)
Your answer will be in calories.
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