Question

The magnitude of the electric field between the plates of a parallel plate capacitor is 3.0X10^5 N/C. Each plate carries a charge whose magnitude is 0.17 µC. What is the area of each plate?

Answer 1

E = 32*10^5 N/C
= (surface charge density)/epsilon0

Solve for the plate area (of each plate) using
A = (total charge)/(surface charge density)

Answer 2

that doesnt make sense...