Question
A stone is thrown directly upwards with an initial speed of 34.5 m/s . What is the maximum height the stone will reach?
Answers
drwls
Maximum height is reached when all of the inital kinetic energy is converted to gravitational potential energy. This happens at height H given by
(1/2) M Vo^2 = M g H
H = Vo^2/(2g)
Vo is the initial velocity and g is the accleration of gravity.
(1/2) M Vo^2 = M g H
H = Vo^2/(2g)
Vo is the initial velocity and g is the accleration of gravity.
helper
See the first link below under Related Questions.
A somewhat similar problem was answered.
The link might be helpful if no one else answers.
A somewhat similar problem was answered.
The link might be helpful if no one else answers.