Asked by Melody
The length of a rectangular flower garden is 6 more feet than its width. A walkway 3 feet wide surrounds the outside of the garden. The total area of the walkway itself is 288 square feet. Find the dimensions of the garden.
Answers
Answered by
helper
A = wL
x = width of garden
x + 6 = length of garden
Area of garden = x(x + 6)
x + 6 = width of garden and walkway
x + 6 + 6 = x + 12 = length of garden and walkway
Area of garden and walkway =
(x + 6)(x + 12)
Area of garden and walkway - 288 = area of garden
(x + 6)(x + 12) - 288 = x(x + 6)
Solve for x, width of garden
x + 6 = length of garden
x = width of garden
x + 6 = length of garden
Area of garden = x(x + 6)
x + 6 = width of garden and walkway
x + 6 + 6 = x + 12 = length of garden and walkway
Area of garden and walkway =
(x + 6)(x + 12)
Area of garden and walkway - 288 = area of garden
(x + 6)(x + 12) - 288 = x(x + 6)
Solve for x, width of garden
x + 6 = length of garden
Answered by
Anonymous
18 by 24
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