Question

Three liquids that will not mix are poured into a cylindrical container. The volumes and densities of the liquids are 0.35 L, 2.6 g/cm3; 0.25 L, 1.0 g/cm3; and 0.40 L, 0.60 g/cm3. What is the force on the bottom of the container due to these liquids? One liter = 1 L = 1000 cm3. (Ignore the contribution due to the atmosphere.)

Answer 1

The force at the bottom is the combined weight of all three liquids. If you want it in Newtons, multiply the total mass (in kg) by g = 9.8 m/s^2

Answer 2

thanks