Asked by Rachel
i) The two lines 4x-6y=-5, and 7x+6y=7 intersect at the point where x= and y=?
ii) If the line 7x+ky=7 is parallel to 4x-6y=-5, then what is the value of k? Answer: k = ?
ii) If the line 7x+ky=7 is parallel to 4x-6y=-5, then what is the value of k? Answer: k = ?
Answers
Answered by
Reiny
The two equations are easy to solve, just add up the two equations and the y term will drop out to get
11x = 2
x = 2/11
sub back into the second (or the first) to get
7(2/11) + 6y = 7
times 11
14 + 66y = 77
66y = 63
y = 63/66 = 21/22
slope of first line = -7/k
slope of 2nd line = 4/6 = 2/3
so -7/k = 2/3
cross-multiply
2k = -21
k = -21/2
11x = 2
x = 2/11
sub back into the second (or the first) to get
7(2/11) + 6y = 7
times 11
14 + 66y = 77
66y = 63
y = 63/66 = 21/22
slope of first line = -7/k
slope of 2nd line = 4/6 = 2/3
so -7/k = 2/3
cross-multiply
2k = -21
k = -21/2
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.