Each side = 3 inches
By drawing a line from the center of the base to the top vertex you'll divide the triangle into two triangles.
The base = 1.5"
a^2 + b^2 = c^2
a^2 + 1.5^2 = 3^2
a^2 + 2.25 = 9
a^2 = 6.75
a = 2.6
A = 1/2bh
A = (1/2) * 1.5 * 2.6
A = ?
Find the area of an equilateral triangle (regular 3-gon) with the given measurement.
9-inch perimeter
A = sq. in.
2 answers
A=(1/2)*(base)*(height)
Side length=(1/3)*(9)=3
Split the triangle in half. This will give you the base, 1.5 in.
If you can image, you have two hypotenuse triangles. To find the height, you need to find the length of the line used to split the triangle in half. So, using Pythagorean Theorem, A^2 + B^2 = C^2 or (1.5)^2 + B^2 = (3)^2.
Side length=(1/3)*(9)=3
Split the triangle in half. This will give you the base, 1.5 in.
If you can image, you have two hypotenuse triangles. To find the height, you need to find the length of the line used to split the triangle in half. So, using Pythagorean Theorem, A^2 + B^2 = C^2 or (1.5)^2 + B^2 = (3)^2.
3 answers