Ask a New Question

Question

A toy car coasts uphill at 2.34 m/s. It accelerates at -.34 m/s squared. How long will it take the car to stop.What equation would I use.
14 years ago

Answers

drwls
Vo = a * T
where a = 0.34 m/s^2 and Vo = 2.34 m/s
That is how long it takes to reach a velocity of zero.
(Ignore the minus sign on a)
Solve for T
14 years ago
ken
t=(Vfinal - Vintial)/ acceleration
time= (0-2.34m/s)/ -.34m/s^2
time=6.88seconds
13 years ago

Related Questions

A car of mass 907 kg coasts on a level road, starting with an initial speed of 14.2 m/s and coming t... A car coasts (engine off) up a 30 degree grade. If the speed of the car is 25m/s at the bottom of t... A boy coasts down a hill on a sled, reaching a level surface at the bottom with a speed of 6.9 m/s.... A 1,600 kg car coasts down a hill starting from rest and decreases its height by 22 m over a distanc... A 61 - kg ice skater coasts with no effort for 61 m until she stops. If the coefficient of kinetic f... if margaret ran 8 km/h uphill for 45 minutes on her way came down at 24 km/h what was her average sp... 1. A skateboarder coasts at a constant velocity toward a ramp with a 15 angle, preparing for the b... A cyclist coasts up a 10.3° slope, traveling 16.0 m along the road to the top of the hill. If the cy... when parking uphill in a car with a manual transmission, you should park with the transmission in... When parking uphill without a curb, you should turn your wheels to the Responses left left...
Ask a New Question
Archives Contact Us Privacy Policy Terms of Use