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A 5kg bullet fired from a gun at 725m/s becomes embedded in a .50kg block of wood that is free to move along a surface and the...Asked by ricki
A 5kg bullet fired from a gun at 725m/s becomes embedded in a .50kg block of wood that is free to move along a surface and the coefficient of friction .355 between the surface and block of wood. find the distance it slides acroos the table.
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Answered by
Anonymous
LOL had the same question as you, this is the help I got:
Use conservation of momentum to get the initial velocity of the block with imbedded bullet.
Then set the initial kinetic energy of block & bullet equal to the work done against friction, and solve for trhe sliding distance.
Check to make sure the bullet weight is really 5 kg. That is more like a cannonball. I suspect it is really 5 g.
Use conservation of momentum to get the initial velocity of the block with imbedded bullet.
Then set the initial kinetic energy of block & bullet equal to the work done against friction, and solve for trhe sliding distance.
Check to make sure the bullet weight is really 5 kg. That is more like a cannonball. I suspect it is really 5 g.
Answered by
ricki
can you tell me the formulas to use
Answered by
drwls
Now that you've had the help, have you tried applying it?
Answered by
ricki
yes, but i don't think that i am applying it the right way.
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