what volume of 1.015mol/L magnesium hydroxide is needed to neutralize 40.0mL of 1.60mol/L hydrochloric acid.

Can you work it out please? Thanks!

1 answer

Write the equation and balance it.
Mg(OH)2 + 2HCl ==> MgCl2 + 2H2O

moles HCl = M x L = ??
moles Mg(OH)2 (look at the coefficients in the balanced equation) needed = 1/2 moles HCl
M HCl = moles HCl/L HCl
Solve for L and convert to mL.