Write an equation of the line containing the point and perpendicular (4,-8);2x+5y=4. I still don't get it. I really appreciate your help.

Answer 1

2x + 5y = 4
Add -2x to both sides
5y = -2x + 4
divide both sides by 5
y = -2/5 y + 4/5
So, slope m = -2/5

Perpendicular lines, the slopes are negative reciprocals of each other.
Slope = -2/5
m1 * m2 = -1
-2/5 * m2 = -1
m2 = -1/(-2/5)
m2 = 5/2

Now you have to find b, for the equation of the perpendicular line.
y = mx + b
m = 5/2
y = 5/2 x + b
P(4, -8)
-8 = 5/2 (4) + b
-8 = 20/2 + b
-8 = 10 + b
-18 = b

y = 5/2 x + b
y = 5/2 + -18
y = 5/2 - 18

Follow these exact steps.

Answer 2

Esther, check your 1-26,2

Esther, check your 1-26,2:54am post.