Asked by lala
A clump of soft clay is thrown horizontally from 30.63 m above the ground with a speed of 30.0 m/s. Where is the clay after 3.8 s? Assume it sticks in place when it hits the ground
Answers
Answered by
bobpursley
lets do the altitude first.
hf=30.63-1/2 g (3.8^2)indicates it is on the ground
now the horizontal position: From solving for time above, when it hit the ground
0=30.63-4.8t^2 >> t= 2.50 sec
so it went horizonally 30*2.5 m.
hf=30.63-1/2 g (3.8^2)indicates it is on the ground
now the horizontal position: From solving for time above, when it hit the ground
0=30.63-4.8t^2 >> t= 2.50 sec
so it went horizonally 30*2.5 m.
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