Asked by Megan Brown
A coffee manufacturer wants to market a new blend of coffee that will sell for $3.90 per pound by mixing two coffees that sell for $2.75 per pound and $5 per pound, respectively. What amounts of each coffee should be blended to obtain 100 pounds of the desired mixture? Thanks so much if anyone can help me with this.
Answers
Answered by
helper
x = lbs of cheaper coffee
2.75x = value of cheaper
100 - x = lbs of better coffee
5(100 - x) = value of better
100 = lbs of mixture
3.90(100) = value of mixture
2.75x + 5(100 - x) = 3.90(100)
Solve for x, lbs of cheaper
100 - x = lbs of better
2.75x = value of cheaper
100 - x = lbs of better coffee
5(100 - x) = value of better
100 = lbs of mixture
3.90(100) = value of mixture
2.75x + 5(100 - x) = 3.90(100)
Solve for x, lbs of cheaper
100 - x = lbs of better
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