Asked by Ray Scholz
Could someone check this matrix calculation
The first matrix dimension is 1 by 3
row 1 = 1
row 2 = 7
row 3 =3
Second matrix is 1 by 3
Row 1 column one =2
row 1 column two = -5
row one column three = 5
my calculation is that it would be the dimensions of 3 by 3
Final calcs would be row 1 column 1 = 2
row one-column two = -1
row one column three = 5
row two column 1 = 14
row two column two= -7
row two column three = 35
row three column one = 6
row three column two = -3
row three column three = 15
Is that correct?
The first matrix dimension is 1 by 3
row 1 = 1
row 2 = 7
row 3 =3
Second matrix is 1 by 3
Row 1 column one =2
row 1 column two = -5
row one column three = 5
my calculation is that it would be the dimensions of 3 by 3
Final calcs would be row 1 column 1 = 2
row one-column two = -1
row one column three = 5
row two column 1 = 14
row two column two= -7
row two column three = 35
row three column one = 6
row three column two = -3
row three column three = 15
Is that correct?
Answers
Answered by
Reiny
when you describe the first matrix as
row 1 = 1
row 2 = 7
row 3 =3
you are describing a column matrix with dimension 3 by 1 , not 1 by 3
so I see you multiplying
1
7
3
by
2 -5 5
I got
2 -5 5
14 -35 35
6 -15 15
I am used to this notation :
m by n matix has m rows and n columns
Are you not using that same notation?
anyway, you could not multiply a 1by3 by a 1by3, no matter what notation you are used to
row 1 = 1
row 2 = 7
row 3 =3
you are describing a column matrix with dimension 3 by 1 , not 1 by 3
so I see you multiplying
1
7
3
by
2 -5 5
I got
2 -5 5
14 -35 35
6 -15 15
I am used to this notation :
m by n matix has m rows and n columns
Are you not using that same notation?
anyway, you could not multiply a 1by3 by a 1by3, no matter what notation you are used to
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.