Asked by Tristan
Nico is saving money for his college education. He invest some money at 8%, and $1300 less than that amount at 5%. the investments produced a total of $234 intrest in 1 yr.How much did he invest at each rate?
Answers
Answered by
Reiny
solve for x
.08x + .05(x-1300) = 234
(I suggest multiplying each term by 100
.08x + .05(x-1300) = 234
(I suggest multiplying each term by 100
Answered by
Tristan
would it be 23 or 2300
Answered by
Reiny
test your answer, but $23 wouldn't make a lot of sense, would it?
(did you multiply both sides by 100?)
(did you multiply both sides by 100?)
Answered by
Tristan
Can somebody help me i still don't get how to do this?
Answered by
Reiny
from my equation :
.08x + .05(x-1300) = 234
times everybody by 100
8x + 5(x-1300) = 23400
8x + 5x - 6500 = 23400
13x = 29900
x = 2300
so larger amount = $2300
smaller investment = 1000
check:
.08(2300) + .05(1000) = 234
.08x + .05(x-1300) = 234
times everybody by 100
8x + 5(x-1300) = 23400
8x + 5x - 6500 = 23400
13x = 29900
x = 2300
so larger amount = $2300
smaller investment = 1000
check:
.08(2300) + .05(1000) = 234
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