Question

A 0.025 kg golf ball moving at 27 m/s crashes through the window of a house in 5.0 10-4 s. After the crash, the ball continues in the same direction with a speed of 10 m/s. Assuming the force exerted on the ball by the window was constant, what was the magnitude of this force?

Answer 1

m= .025 kg
initial velocity= 27 m/s
time= 5.0*10^-4
final velocity= 10 m/s

Force*time=mass( final vecolicy - negative initial velocity)

F(5.0*10^-4)=(.025)(10-(-27))

F=(.025)(10-(-27))/(5.0*10^-4)

Answer 2

1850 N