Asked by angel
                3x+5y=0    2x-5y=-9
idk how 2 solve it then graph it my teacher eont help me plzz help
            
        idk how 2 solve it then graph it my teacher eont help me plzz help
Answers
                    Answered by
            helper
            
    I assume you need to solve these equations simultaneously ?
3x + 5y = 0
2x - 5y = -9
Solving by elimination method. The object is to eliminate one of the variables, either x or y.
Since you have +5y in the first equation and -5y in the second equation, you ADD the two equations.
This is because +5y + -5y = 0.
3x + 5y = 0
2x - 5y = -9
5x + 0 = -9
5x = -9
Divide both sides by 5
x = -9/5
To find y, substitute x = -9/5 in either equation and solve for y.
3x + 5y = 0
x = -9/5
3(-9/5) + 5y = 0
-27/5 + 5y = 0
Add 27/5 to both sides
-27/5 + 27/5 + 5y = 27/5
5y = 27/5
Divide both sides by 5
y = 27/5 /5
Multiplying the numerator by the reciprocal of the denominator is the same as dividing.
y = 27/5 * 1/5
y = 27/25
I'll leave the check to you.
x = -9/5, y = 27/5
    
3x + 5y = 0
2x - 5y = -9
Solving by elimination method. The object is to eliminate one of the variables, either x or y.
Since you have +5y in the first equation and -5y in the second equation, you ADD the two equations.
This is because +5y + -5y = 0.
3x + 5y = 0
2x - 5y = -9
5x + 0 = -9
5x = -9
Divide both sides by 5
x = -9/5
To find y, substitute x = -9/5 in either equation and solve for y.
3x + 5y = 0
x = -9/5
3(-9/5) + 5y = 0
-27/5 + 5y = 0
Add 27/5 to both sides
-27/5 + 27/5 + 5y = 27/5
5y = 27/5
Divide both sides by 5
y = 27/5 /5
Multiplying the numerator by the reciprocal of the denominator is the same as dividing.
y = 27/5 * 1/5
y = 27/25
I'll leave the check to you.
x = -9/5, y = 27/5
                    Answered by
            angel
            
    o ok ty
    
                    Answered by
            helper
            
    You're welcome.
    
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