Asked by Chloe
I am having trouble figuring out how to solve this logarithms. Could someone please help!
log2(log4x)=1 and
solve for x and y:
(1/2)^x+y= 16 logx-y8=-3
log2(log4x)=1 and
solve for x and y:
(1/2)^x+y= 16 logx-y8=-3
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