Asked by muna
the three points g(4,0) ,h(h,6) and i(7,1) are such that gh is twice as long as gi .calculate the two possible values of h.
Answers
Answered by
Damon
gi^2 = 3^2+1^2 = 10^2
gh^2 = 4 * 10^2
4*10^2 = (h-4)^2 + 36
400 = h^2 - 8h + 36
h^2 - 8 h - 364 = 0
h = [ 8 +/- sqrt(64+1456) ]/2
h = 4 +/- 19.5
h = 23.5 or -15.5
check my arithmetic !
gh^2 = 4 * 10^2
4*10^2 = (h-4)^2 + 36
400 = h^2 - 8h + 36
h^2 - 8 h - 364 = 0
h = [ 8 +/- sqrt(64+1456) ]/2
h = 4 +/- 19.5
h = 23.5 or -15.5
check my arithmetic !
Answered by
hw
using distance formula
d of GI= square root of 10-3.1622
twice this is the square root of 40
could be- 6 or 2
d of GI= square root of 10-3.1622
twice this is the square root of 40
could be- 6 or 2
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