Asked by Jessica
Nitrogen reacts with hydrogen to make ammonia: N2 + 3H2 -> 2NH3
Calculate the maximum thoeretical yield of ammonia that can be made by reacting 90g of hyrdrogen with an excess of nitrogen.
Thanks!
Calculate the maximum thoeretical yield of ammonia that can be made by reacting 90g of hyrdrogen with an excess of nitrogen.
Thanks!
Answers
Answered by
DrBob222
Write the equation and balance it.
Convert 90 g H2 to mols. mols = g/molar mass.
Convert mols H2 to mols NH3 by using the coefficients in the balanced equation.
Convert mols NH3 to grams NH3.
g NH3 = mols NH3 x molar mass NH3. That is the theoretical yield.
Convert 90 g H2 to mols. mols = g/molar mass.
Convert mols H2 to mols NH3 by using the coefficients in the balanced equation.
Convert mols NH3 to grams NH3.
g NH3 = mols NH3 x molar mass NH3. That is the theoretical yield.
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